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Research report · Not peer reviewed · Chowla’s general conjecture remains open

The Mathematics of Sound and the Search for Negative Peaks

CliDeck Research Notes · Bass Plus · 18 October 2026

Abstract

How far below its average must a collection of synchronized waves fall? This question leads from a simple model of sound to Chowla's cosine problem, a difficult question about sums of distinct integer frequencies. This report brings together a sequence of ninety exploratory approaches, their mathematical checks, and their limitations. It develops exact examples, a spectral interpretation, a counterexample to minimum detection by a natural sampling grid, and an explicit approximation bound whose sufficient polynomial degree depends on the number of frequencies and the requested error, but not on the largest frequency. The approximation method belongs to Lasserre's established pushforward measure hierarchy; its Chebyshev filtering mechanism is closely related to work of Slot and Laurent. We claim neither a solution of Chowla's conjecture nor priority for this general method. The useful outcome is a reproducible account of what can be proved, what finite computations show, and which tempting extensions fail. Eight figures connect the analysis to phase locking, sampling, weighted amplitudes, spectral bands, and finite searches.

1. The question behind the waves

Take a finite set of distinct positive integers AA, and let N=∣A∣N=|A|. We study the real function

fA(x)=∑a∈Acos⁡(ax),x∈[0,2π]. f_A(x)=\sum_{a\in A}\cos(ax),\qquad x\in[0,2\pi].

Every component has amplitude one. Every initial phase is zero. There is one common variable xx: the components cannot choose their phases independently. Define the depth of the most negative excursion by

K(A)=−min⁡x∈[0,2π]fA(x). K(A)=-\min_{x\in[0,2\pi]}f_A(x).

Chowla's question asks whether there is an absolute constant c>0c>0 such that

K(A)≥cN K(A)\ge c\sqrt{N}

for every such set AA. The constant would have to work for consecutive frequencies, sparse frequencies, sets with strong arithmetic relations, and arbitrarily large frequency values. There is no upper bound on max⁡A\max A in the question. Recent papers make substantial progress on weaker polynomial lower bounds, but the sources consulted for this report continue to distinguish that progress from the square-root target. JMTZ2025 Bedert2026 Shankar2026

The quantifiers are the heart of the problem. Finding a large negative excursion for a particular set is valuable, but proving it for every finite set is a different task. Replacing cc by the set-dependent number c(A)=K(A)/Nc(A)=K(A)/\sqrt N is an exact description, not a resolution: one must still prove that the infimum of this function stays positive over all sets and all sizes.

For a sound interpretation, set x=2πν0tx=2\pi\nu_0t, where ν0\nu_0 is a base frequency in hertz. Then the physical frequencies are aν0a\nu_0. The mathematical model describes an ideal harmonic signal with equal amplitudes and synchronized phases. Music and equalized audio usually have unequal amplitudes, changing phases, noise, and finite observation windows. The model helps explain interference and measurement; it does not, by itself, establish a benefit of an audio product.

2. What the coefficient means physically

Use normalized averaging over a full period:

E[g]=12π∫02πg(x) dx. \mathbb E[g]=\frac1{2\pi}\int_0^{2\pi}g(x)\,dx.

Orthogonality gives E[fA]=0\mathbb E[f_A]=0 and E[fA2]=N/2\mathbb E[f_A^2]=N/2. Thus the root-mean-square amplitude is N/2\sqrt{N/2}, while fA(0)=Nf_A(0)=N. All signals in this model have the same RMS amplitude when they have the same number of frequencies. Their negative peaks can nevertheless differ.

For example,

K({1,2})=98,K({1,3})=2. K(\{1,2\})=\frac98,\qquad K(\{1,3\})=2.

For the first set, put u=cos⁡xu=\cos x and complete the square:

cos⁡x+cos⁡2x=2(u+14)2−98. \cos x+\cos 2x=2\left(u+\frac14\right)^2-\frac98.

For the second, both cosines equal −1-1 at x=πx=\pi. The first signal has a shallower trough despite identical RMS amplitude. The dimensionless negative crest factor is

CF−(A)=K(A)N/2=2 K(A)N. \mathrm{CF}_{-}(A)=\frac{K(A)}{\sqrt{N/2}}=\sqrt2\,\frac{K(A)}{\sqrt N}.

This explains the normalization: cc would be a uniform lower bound on a normalized negative peak. It is not an energy quantum, a material constant, or a new universal constant of physics.

Two waveforms have equal RMS but different negative peaks. A two-dimensional phase diagram shows a constrained path that never reaches the point where both cosines would be minus one.Figure data (JSON) · SVG · PNG

Figure 1. Phase locking changes the attainable trough. The two signals have equal RMS amplitude. For A={1,2}A=\{1,2\}, the hypothetical independent-phase value −2-2 is inaccessible; the exact common-phase minimum is −9/8-9/8. The chart keeps the hypothetical model explicitly separate from the actual signal.

Explore interactively

If fAf_A represents acoustic pressure relative to equilibrium, negative values describe rarefaction. They do not mean negative acoustic energy. In the plane progressive-wave approximation, average intensity is proportional to mean-square pressure, with proportionality determined by acoustic impedance. This physical distinction matters whenever a proposed proof replaces a signed wave amplitude by a squared magnitude. BakerAcoustics

3. Why a single common phase is restrictive

The vector (cos⁡(a1x),…,cos⁡(aNx))(\cos(a_1x),\ldots,\cos(a_Nx)) follows a one-parameter path. For multiple frequencies, it does not explore the entire cube [−1,1]N[-1,1]^N. For A={1,2}A=\{1,2\}, the relation cos⁡2x=2cos⁡2x−1\cos2x=2\cos^2x-1 prevents both coordinates from being −1-1 at once. Allowing separate phases removes that constraint and changes the problem.

The same point becomes geometric with three frequencies. The path

x⟼(cos⁡x,cos⁡2x,cos⁡3x) x\longmapsto (\cos x,\cos2x,\cos3x)

is a curve inside a cube. Colouring each point by the sum of its coordinates shows exactly which signal values this shared clock can reach. A rotation of the display changes our viewpoint, not the set of attainable states. This is why a three-dimensional figure is useful here: its geometry represents an actual constraint.

A three-dimensional curve of three harmonic amplitudes is coloured by their sum. The corner where all three amplitudes would be minus one is marked separately because it is inaccessible to a common phase.Figure data (JSON) · SVG · PNG

Figure 2. One clock traces a curve, not a cube. The colour is the actual sum cos⁡x+cos⁡2x+cos⁡3x\cos x+\cos2x+\cos3x. The corner (−1,−1,−1)(-1,-1,-1) is not on the curve. Over a full period, the real cosine-coordinate curve is retraced. The figure is a classical phase model, not a visualization of a quantum state.

Multiplying every frequency by the same positive integer dd has a different effect. Since fdA(x)=fA(dx)f_{dA}(x)=f_A(dx), it compresses the pattern in time while preserving its full-period range:

K(dA)=K(A). K(dA)=K(A).

A trough can become narrower in a local time window without becoming shallower. Any argument that estimates the total negative contribution from one local width must account for the increased number of repeated troughs.

Two stacked waveforms show the same shape once and five times across the same reference interval. Both have exact negative depth 9/8 and RMS amplitude 1.Figure data (JSON) · SVG · PNG

Figure 3. Frequency scale and peak depth are different quantities. The sets {1,2}\{1,2\} and {5,10}\{5,10\} both have K=9/8K=9/8. Dilation produces more oscillations within the same displayed interval. It does not improve the normalized negative minimum.

4. A sampling grid can hide the trough

Consider A={1,…,N}A=\{1,\ldots,N\} and let q=2N+1q=2N+1. On the equally spaced grid xj=2πj/qx_j=2\pi j/q, a roots-of-unity identity gives

fA(x0)=N,fA(xj)=−12(1≤j<q). f_A(x_0)=N,\qquad f_A(x_j)=-\frac12\quad(1\le j<q).

The grid therefore reports a negative depth of only 1/21/2. It also reports the correct mean-square value:

1q∑j=0q−1fA(xj)2=N2. \frac1q\sum_{j=0}^{q-1}f_A(x_j)^2=\frac N2.

Yet at the point between grid locations x=3π/qx=3\pi/q, the Dirichlet-kernel identity yields

fA(3π/q)=−12−12sin⁡(3π/(2q)). f_A(3\pi/q)=-\frac12-\frac{1}{2\sin(3\pi/(2q))}.

Consequently,

K(A)≥12+q3π. K(A)\ge\frac12+\frac{q}{3\pi}.

The hidden excursion grows linearly with NN. This is an exact family of counterexamples to using the smallest raw sample as the true minimum. It is not a failure of trigonometric interpolation: the same grid contains enough information to reconstruct this finite-bandwidth trigonometric polynomial. Reconstructing a signal and simply taking the smallest of its stored samples are different operations.

A full-period waveform and a close-up show a deep negative trough between two sample points. The exact sample values are −1/2 away from the origin; an analytic point in the trough is below −3.Figure data (JSON) · SVG · PNG

Figure 4. Correct RMS does not certify the minimum. For N=12N=12 and q=25q=25, every nonzero sample is −1/2-1/2, while the continuous curve passes much lower between samples. The highlighted off-grid point is an exact witness. The drawn smooth curve is an illustration, not a substitute for the identity.

A simple rigorous guard is available for a general set. For a grid with MM equally spaced points, let KMK_M be minus the smallest sample. The derivative bound ∣fA′∣≤∑a|f_A'|\le\sum a gives

KM≤K(A)≤KM+πM∑a∈Aa. K_M\le K(A)\le K_M+\frac\pi M\sum_{a\in A}a.

A second-derivative argument at a true minimum improves the error bound to π2∑a2/(2M2)\pi^2\sum a^2/(2M^2) when that is smaller. A scientific interactive chart should display the certified interval alongside the sampled value. A dense curve by itself does not supply a certificate.

5. The same function as a lattice spectrum

There is an exact way to reinterpret the cosine sum as a particle-like hopping model. Let TT be the bilateral shift on square-summable sequences indexed by the integers, and define

HA=12∑a∈A(Ta+T−a). H_A=\frac12\sum_{a\in A}(T^a+T^{-a}).

Fourier transformation turns each shift into a complex phase. The operator becomes multiplication by fA(x)f_A(x), so its spectrum is the full interval

σ(HA)=[−K(A),N]. \sigma(H_A)=[-K(A),N].

This is a mathematical identity. The wave minimum becomes the lower edge of the spectrum of a translation-invariant lattice operator. The model is related to tight-binding descriptions of hopping on a lattice. An infinite lattice can have continuous spectral bands even though its sites are discrete; discrete position labels alone do not quantize all possible energies. TongAQM

A finite ring introduces a boundary condition. With qq sites and a phase twist ϕ\phi, its eigenvalues are

Ej(ϕ)=fA ⁣(2πj+ϕq),0≤j<q. E_j(\phi)=f_A\!\left(\frac{2\pi j+\phi}{q}\right),\qquad 0\le j<q.

At ϕ=0\phi=0, the ring sees one sampling grid. As ϕ\phi varies through a full turn, the eigenvalue curves sweep the entire continuous phase variable. Taking the minimum over both jj and ϕ\phi recovers −K(A)-K(A) exactly. The boundary twist repairs this finite model's missing phases; it does not create a new universal lower bound. Twisted boundary conditions are an established tool in spectral physics. Bardyn2014

A coloured heatmap displays 25 energy branches versus boundary phase, beside their lowest value at each phase. The boundary value −1/2 changes to much deeper energies away from zero twist.Figure data (JSON) · SVG · PNG

Figure 5. A boundary phase reveals what one finite ring misses. The heatmap shows the actual values Ej(ϕ)E_j(\phi) for q=25q=25 and A={1,…,12}A=\{1,\ldots,12\}. The untwisted column has the exceptional two-value spectrum, while other twists expose lower energies. The vertical coordinate labels finite eigenvalue branches rather than an independent sound frequency.

6. A certified way to approximate each minimum

For a real polynomial pp of degree at most dd, consider the weighted average

R(p)=−E[fAp(fA)2]E[p(fA)2]. R(p)=-\frac{\mathbb E[f_Ap(f_A)^2]}{\mathbb E[p(f_A)^2]}.

The denominator is positive for nonzero pp because fAf_A is nonconstant and its range contains an interval. The nonnegative weight p(fA)2p(f_A)^2 cannot produce an average below the true minimum. Hence R(p)≤K(A)R(p)\le K(A). Optimizing over the polynomial gives

Bd(A)=max⁡0≠p, deg⁡p≤dR(p)≤K(A). B_d(A)=\max_{0\ne p,\,\deg p\le d}R(p)\le K(A).

These lower estimates of the depth increase with dd. They can be expressed as a generalized eigenvalue problem in moments μk=E[fAk]\mu_k=\mathbb E[f_A^k]. The sign convention matters: the corresponding estimate of min⁡fA\min f_A is an upper bound, while its negative is a lower bound on K(A)K(A).

This is the pushforward measure hierarchy developed by Lasserre, specialized to the distribution of a cosine sum. Permitting a sum of polynomial squares instead of one square gives the same optimal quotient: the quotient for a sum is a weighted average of the individual quotients. The construction and its basic convergence are established prior work. Lasserre2021

The report provides an explicit sufficient degree tailored to the present family. For 0<ε≤N0<\varepsilon\le N, set

M=⌈8πNε⌉. M=\left\lceil\frac{8\pi N}{\varepsilon}\right\rceil.

Then the mathematical appendix proves that

d≥⌈Nε[Nlog⁡M+log⁡ ⁣(16Nε)]⌉⟹0≤K(A)−Bd(A)≤ε. d\ge\left\lceil\sqrt{\frac N\varepsilon}\left[N\log M+\log\!\left(\frac{16N}{\varepsilon}\right)\right]\right\rceil \quad\Longrightarrow\quad 0\le K(A)-B_d(A)\le\varepsilon.

The logarithm is natural. The sufficient degree depends on NN and the requested absolute error, but not on max⁡A\max A. The proof first shows that a set of phases close to a minimum has a uniform positive measure, using a partition of the phase torus. A Chebyshev polynomial then gives that region a sufficiently large relative weight. The underlying filtering architecture is closely related to the needle-polynomial analyses of Slot and Laurent. The frequency-independent specialization and its constants are proved here for review; their priority has not been established. SlotLaurent2021 SlotLaurent2022 NISTDLMF

Five exact rational trial bounds approach the known negative depth 9/8. A second panel displays the exact remaining gaps on a logarithmic scale.Figure data (JSON) · SVG · PNG

Figure 6. A valid approximation can improve without solving the conjecture. For A={1,2}A=\{1,2\}, an explicitly chosen Chebyshev trial polynomial gives exact rational values at the highlighted degrees, approaching the known depth 9/89/8. These are values of a particular trial quotient RdR_d, not the optimized hierarchy BdB_d. The comparison line is an exact minimum in this special example.

This result answers an approximation question for each input. It does not answer the extremal question over all inputs. The degree may be large, exact moments may be expensive to compute, and a generalized eigenvalue calculated in floating point requires an error certificate before being called exact. A finite sufficient degree is not a claim of practical polynomial runtime in the input length.

Some failed extensions have clean mathematical explanations. Their value is to prevent the same obstruction from being mistaken for progress again.

Unequal amplitudes change the theorem

For weights wa=1−a/(N+1)w_a=1-a/(N+1) on a=1,…,Na=1,\ldots,N, the Fejér-kernel identity gives

∑a=1Nwacos⁡(ax)=FN(x)−12≥−12, \sum_{a=1}^{N}w_a\cos(ax)=\frac{F_N(x)-1}{2}\ge-\frac12,

and equality is attained. Meanwhile ∑wa2=N(2N+1)/(6(N+1))\sum w_a^2=N(2N+1)/(6(N+1)) grows linearly in NN. Therefore the negative depth divided by the coefficient norm tends to zero. Multiplying by N+1N+1 gives positive integer weights and the same failure after normalization. Making amplitudes integer-valued does not restore the unit-amplitude conjecture.

Unit and tapered amplitudes produce different waveforms on the same twelve frequencies. A second graph shows the exact normalized negative depth of the tapered family tending to zero as the number of frequencies increases.Figure data (JSON) · SVG · PNG

Figure 7. A sharp positive pulse can coexist with a fixed negative floor. Fejér weights give an exact depth of 1/21/2 while the coefficient norm grows. The companion normalization plot explains why this is a counterexample to a weighted extension, not to Chowla's original equal-amplitude problem.

A physically inspired weight can emphasize too little

The logistic or Fermi–Dirac-inspired weight wβ(x)=1/(1+eβfA(x))w_\beta(x)=1/(1+e^{\beta f_A(x)}), with β≥0\beta\ge0 and threshold fixed at zero, defines a valid lower estimate

Bβ=−E[fAwβ]E[wβ]. B_\beta=-\frac{\mathbb E[f_Aw_\beta]}{\mathbb E[w_\beta]}.

For consecutive frequencies, the appendix proves Bβ≤20+10log⁡(2N+1)B_\beta\le20+10\log(2N+1) for every β\beta. Choosing a larger inverse-temperature parameter cannot turn this particular family into a square-root certificate on every input. An adjustable threshold would be a different family and is not ruled out by this statement.

A promising finite minimum remains finite evidence

Another nonnegative weight is the Riesz product ∏a∈A(1−cos⁡ax)\prod_{a\in A}(1-\cos ax). Its associated quotient can be calculated exactly from integer Laurent-polynomial coefficients. The recorded exhaustive calculation checks all 262,143262{,}143 nonempty subsets of {1,…,18}\{1,\ldots,18\}. On that finite domain, the smallest normalized quotient is 7/207/20, attained at A={1,2,3,4,5,7,9,11,13}A=\{1,2,3,4,5,7,9,11,13\}.

Points show minimum normalized Riesz-product trial bounds by subset size in one finite frequency domain. Several lie below one half; the smallest is seven twentieths at size nine.Figure data (JSON) · SVG · PNG

Figure 8. A finite search suggests questions; it does not settle all frequencies. The plotted minima are grouped by set size within the fixed universe {1,…,18}\{1,\ldots,18\}. The value 7/207/20 is an exact finite-domain result. The rejected candidate 1/21/2 fails already for A={1,2,3}A=\{1,2,3\}. No universal lower bound for this Riesz quotient is claimed.

8. What the quantum analogy contributes

The wave-to-lattice correspondence is useful because it is exact and preserves the quantity being studied. Other quantum analogies need an equally explicit dictionary. For a harmonic oscillator, a number state has zero mean displacement even when it has nonzero occupation. A coherent state can have a sinusoidal mean displacement, while its mean occupation need not be an integer. The integer spectrum of the number operator does not force the Fourier coefficients of a classical waveform to be integers. Squeezing changes quadrature variances; it need not change the mean waveform. Cappellaro2012 Shapiro6453

Experiments can control individual mechanical quanta, so phonons are physical rather than merely metaphorical. That does not transfer a quantum measurement theorem to a signed classical cosine sum without proof. OConnell2010 In this investigation, the productive question was not whether an analogy sounded surprising, but whether it preserved amplitudes, phases, averaging, and the minimum. The catalogue records where those requirements succeeded and where they failed.

9. Evidence, provenance, and the remaining problem

The companion mathematical appendix supplies full proofs and separates identities, inequalities, and finite examples. The research catalogue indexes ninety numbered approaches and an earlier unnumbered groundwork stage. The archive includes the preserved source notes, code, result files, and three sealed historical archives. It also identifies corrections that supersede earlier statements.

A selected reproduction of the early groundwork checked all 4,194,3034{,}194{,}303 nonempty subsets of {1,…,22}\{1,\ldots,22\} with two different enumeration procedures. Both found the same unique minimizer of K(A)/∣A∣K(A)/\sqrt{|A|} within that finite universe: A={1,2,3,4,5,6,7,8,10,11,13,14,15,16,17,21}A=\{1,2,3,4,5,6,7,8,10,11,13,14,15,16,17,21\}. Exact certificates put its depth strictly between 2.45483275302.4548327530 and 2.45483275312.4548327531. This concerns the actual continuous minimum; the separate Riesz calculation above concerns a particular lower-estimate method. Neither finite result covers arbitrarily large frequencies. The reproduction report and its machine-readable outputs are included in the archive.

There is a material provenance limitation: approaches 41–50 were reconstructed from surviving descriptions rather than recovered as original bytes. In particular, the earlier claim involving 1,980 finite certificates for approach 42 cannot be represented as a reproduced certificate set; those files are missing. A separately available tail argument has a different verification status. These distinctions are documented in the catalogue and provenance notes.

The checks in this project consist of mathematical derivations, exact arithmetic programs, independent calculations within this workflow, and reproducible numerical illustrations. They are not external peer review or formal proof-assistant verification. ChatGPT assisted the writing, derivations, literature comparison, and code preparation. No claim of independent verification by OpenAI is made.

What remains is precise: prove a positive universal lower bound for K(A)/∣A∣K(A)/\sqrt{|A|}, or produce a valid sequence of unit-amplitude, zero-phase, distinct positive integer frequency sets for which that ratio tends to zero. None of the weighted examples, finite grids, independent-phase models, or finite searches in this report accomplishes either task. The present contribution is a checked collection of tools and obstructions, with a clear route for readers to inspect and extend the work.

Further reading and supporting material

The accompanying pages are Sampling and Hidden Peaks, Waves and Lattice Particles, Certified Minimum Estimates, The Limits of Wave Analogies, Research Catalogue of Ninety Approaches, and the Mathematical Appendix. Full bibliographic entries appear on the References page. The downloadable research edition includes all of these texts and the reproducibility materials.

The Mathematics of Sound and the Search for Negative Peaks | Bass Plus